In Schweser’s Mock there’s a question that asks to calculate the value of a bond with the following information.
Maturity: 3 years
Option: Callable at par in 1 year
Coupon: 2%
Par value $100
The interest rate tree is
Year 0 = 1.5%
Year 1, upper node = 2.8873%
Year 1, lower node = 1.9354%
Year 2, upper node = 4.1328%
Year 2, middle node = 2.7703%
Year 2, lower node = 1.8570%
The value I get for the lower node in year 2 is $100.14 (obtained from 102/1.01857) so since the value is higher than par, I believe it should be called and so the value should be $100, but according to the answer it is not. The answer simply uses $100.14.
Option: Callable at par in 1 year : This solves your assumed big problem clearly the Bond is not Callabe at T=2 now because in all the examples you have been doing in Schweser the bonds where being called at T=1 and T=2 then you rushed to what stuck into your head during practice without necessarily paying attention to the question. On the exam day the answer for your method will be one of the answer options and you will get out of the exam feeling confident. Please read the question carefully.