That explanation is pretty confusing. It is no wonder you didn’t get it. If I only had this info to go by, i would be lost too. The text is comparing the payoffs from a volatility swap and variance swap. If you recall interest rate swaps, these are pretty much the same conceptually. One ends pays a notional amount N times a fixed rate for the volatility, while the other end pays the notional M times the realized volatility. The variance swap is similar, except the notional amount differs. to make things more concrete, let
Nvol be the notional amount for the volatility swap
Nvar be the notional amount for the variance swap
σk be the strike volatility (the fixed rate for the volatility)
σrealized be the realized volatility
then
payoff from variance swap = Nvar x ((σrealized)2 - σk2)
payoff from a volatility swap = Nvol x (σrealized - σk)
it turns out (according to my book anyhow) that Nvar = 1/(2σk) Nvol,
and so the payoff for variance can be rewritten as
payoff from variance swap = Nvol / (2σk) x ((σrealized)2 - σk2)
now, consider what happens when realized volatility is lower than the strike volatility.
that is, σrealized < σk. if we let σrealized = σk - ε , where ε is any positive constant,
and substitute it into the payoff formula, we see that
payoff from variance swap = payoff from volatility swap + a positive constant
this means that, when volatility increases, the payoff for a variance swap is greater than the payoff for a volatility swap. in other words, you lose less money with a variance swap compared to a volatility swap. this is point #1.
next, consider what happens when σrealized > σk.
this time, let σrealized = σk + ε, where once again ε is a positive constant.
if you substitute this into the payoff formula, you’ll find that
payoff from variance swap is also greater than volatility swap. this is point #2.
edit: as for convexity:
A single-variable function that can be differentiated twice is a convex if and only if
the second derivative is non-negative.
i.e. f(x) is convex iff f’’(x) >= 0
otherwise, if f’’(x) <= 0, then it is a concave function.
https://mjo.osborne.economics.utoronto.ca/index.php/tutorial/index/1/cv1/t
here, the book says that the payoff is a convex function of the volatility, and is similar to the convexity of bond prices. in this case, we are treating the payoff as a single variable of the volatility (this is the ‘x’)
as a reminder, the convexity for a bond price is given by
[1/P(i)] x [(d2/di2) P(i)]
the payoff for a variance swap is given by
Payoff = notional x ((σrealized)2 - σk2).
differentiating twice with respect to σrealized results in a positive constant, so
[d2/d(σrealized)2] (Payoff of variance swap) > 0
because the second derivative of the payoff function is positive, by definition it is a convex function.