The null hypothesis is that the slope is zero. If we do not have enough evidence to reject the null hypothesis, then we conclude that the slope might not be significant (i.e., that it might be zero).
n=36 ; Correlation Cooefficient = -0.28 ; significance level = 5% and critical value = 2
Calculated t = -1.7
Clearly we will reject Ho
after this I am confused about significant part.
Do I have to link this with p value to conclude that cooefficient is significant or second option of my original query is just a statement to confuse candidate.
This is not tricky. I think you missing some things.
Correlation coefficient can be from -1 to +1, so its center is Zero. If you check the T-test for testing correlation coefficient significance, you can see that the T-test can be negative too. So, if your calculated t is -1.7, your t critical value must be -2, not 2. Why? Because this is a two-tailed test. In this case, as the calculated t is higher than critical (remeber they are negatives), you FAIL to reject the Ho, or you accept the alternative hypotesis.
I prefer to use the absolute value of the calculated T and the critical values, so I dont get confused when they are negatives.
| calc. T | > | critical value | = Reject Ho
| calc. T | < | critical value | = Fail to Reject Ho (accept the alternative)
(A): I’m agree with your statement. Thats why we cannot say “Accept the alternative”, we say “Fail to reject the null”. I wrote it just to make it easier to differientiate from Fail to Reject Ho (this always a confusing part when learning Hyphotesis test" for students)
(D) Yes, you right, my bad. Df = n - k -1, just rememberd now why you need an adequate or minimal number of observations when your model has many variables. Using many variables and a few observations causes your DF are reduced bad so your Confidence Intervals for coefficients are wider giving you more uncertainty about the results. Models must be parsimonious !