book 6, reading 35, about drawdown:
Maximum DD(m,t) = min([V(m,t) – V(m,t*)/V(m,t*)], 0)
I think it should be Maximum DD(m,t) = min([( V(m,t) – V(m,t*)) /V(m,t*)], 0)
ie in the example, for May 2011: DD = min ([(7.83%-9.06%)/9.06%],0)
book 6, reading 35, about drawdown:
Maximum DD(m,t) = min([V(m,t) – V(m,t*)/V(m,t*)], 0)
I think it should be Maximum DD(m,t) = min([( V(m,t) – V(m,t*)) /V(m,t*)], 0)
ie in the example, for May 2011: DD = min ([(7.83%-9.06%)/9.06%],0)