In the example below were calculating the standard dev of expected returns, and we dont divide by n? Do we only divide by n for populations? or do we only not divide by n for expected returns?
Given the following probability distribution, find the standard deviation of expected returns.
Event P(RA) RA Recession 0.1 -5% Below Average 0.3 -2% Normal 0.5 10% Boom 0.1 31%
Answer:
Find the weighted average return (0.10)(−5) + (0.30)(−2) + (0.50)(10) + (0.10)(31) = 7%.
Next, take differences, square them, multiply by the probability of the event and add them up. That is the variance. Take the square root of the variance for Std. Dev. (0.1)(−5 − 7)2 + (0.3)(−2 − 7)2 + (0.5)(10 − 7)2 + (0.1)(31 − 7)2 = 100.8 = variance.
100.80.5 = 10.04%.
When they give you weights (or probabilities), they’ve already divided by n for you.
Think of it this way: there are 100 (= n) possible future scenarios:
- in 10 of them, the economy is in a recession, and the return is -5%
- in 30 of them, the growth of the economy is below average, and the return is -2%
- in 50 of them, the growth of the economy is normal, and the return is 10%
- in 10 of them, the economy is booming, and the return is 31%
So, when you multiply -5% by 0.1, what you’re really doing is adding -5% + -5% + -5% + -5% + -5% + -5% + -5% + -5% + -5% + -5% (= -50%), then dividing by 100 (= n).
So . . . whenever they give you weights or probabilities, you just multiply each outcome by its weight or probability, and you’re done. (One caveat: if the weights don’t add up to 1.0, then you have to divide by the sum of the weights. That shouldn’t occur on the exam.)
Fantasitc resposnse. Much appreciated!
The quick and dirty rule - if they give you weights or probabilities (the same thing, since probabilities are also weights), you don’t divide by “n”. If they don’t, you’re dividing by N (in the case of averages) or N or N-1 (in the case of variances - N for population variance, N-1 for sample variance.
The “regular” average (dividing by N) is also a weighted average - it’s just that all the weights are equal (and all are equal to “1/(N-1)”)