Ok so this may sound ridicolous, and fankly im feeling like im wastin time because its been over 30minutes trying to solve this small but bothering issue:
I have 46df - 2 -1= 43in the t table. 1% one tail test.
in schewser it states that the critical value is 2.42
How do you get that value??? how do you calculate that? step by step please using the table
thanks a lot!
You want the t-value for 43 d.f. that leaves 1% in one tail. Reading from a random t-table on the web, for 40 d.f. the t-value is 2.423; for 60 d.f. the t-value is 2.39. If we linearly interpolate, then the t-value for 43 d.f. is (17/20)*2.423 + (3/20)*2.39 = 2.41805
thank you. but the thing is that the 2.423 value how do i get it? you saw it online, but the table I have jumps from df=40 to 50
The t-table in appendix B of volume 1 of the 2018 Level II curriculum has a row for 43 degrees of freedom; the critical value for a 1-tail probability of 0.01 is 2.416.
If all you have is 40 dof (2.423) and 50 dof (2.403), then you interpolate: 2.423 + 3/10 × (2.403 − 2.423) = 2.417. Close enough.
I punted all this and I must have lucked out because there wasn’t a single question about t-scores and whatnot.